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9.5=(x^2)-3x=10.5
We move all terms to the left:
9.5-((x^2)-3x)=0
We get rid of parentheses
-x^2+3x+9.5=0
We add all the numbers together, and all the variables
-1x^2+3x+9.5=0
a = -1; b = 3; c = +9.5;
Δ = b2-4ac
Δ = 32-4·(-1)·9.5
Δ = 47
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{47}}{2*-1}=\frac{-3-\sqrt{47}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{47}}{2*-1}=\frac{-3+\sqrt{47}}{-2} $
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